A diatomic gas is heated at constant pressure. If 105J of heat is given to the gas, find (a) the change in internal energy of the gas (b) the work done by the gas.
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Answer:Suppose the volume changes from V
1
to V
2
and the temperature changes from T
1
to T
2
.
The heat supplied at
ΔQ=ΔU+PΔV=ΔU+nRΔT=ΔU+
f
2ΔU
[ΔU=
2
nfRΔT
]
The change in internal energy is
ΔQ=ΔU[1+
f
2
]
$$105=\Delta U\left [1+\frac {2}{5}\right ]\Rightarrow \Delta U=75 J$$
December 27, 2019
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