Math, asked by karanklair, 11 months ago

A dice has its six faces marked 0, 1, 1, 1, 6, 6.Two such dice are thrown together and total score is

recorded.(a)how many different scores are possible? (b) What is the probability of getting a total of seven?​

Answers

Answered by ska150502
7

Answer:

6, 1/3

Step-by-step explanation:

Different scores that are possible as a combination of both dices are thrown -  

(0,0) = 0

(0,1) = 1

(0,6) = 6

(1,1) = 2

(1,6) = 7

(6,6) = 12

To get a score of 7, one dice must show 1 and one dice must show 6.  

Probability of dice getting 1 = 3/6 = 1/2.  

Probability of dice getting 6 = 2/6 = 1/3.  

Thus probability of getting score 7 is =  

1/2 * 1/3 + 1/2*1/3 = 1/3.

Answered by yoelwangsaputra008
1

Answer:

a) there will be 6 different score

b) 1/6

please rate, hope it helps

Step-by-step explanation:

a) there will be 6 different score

using n! = 3!= 3.2.1

that is (00, 01, 06,11, 16,66)

b) then we want to find 1 in the first dice and 6 in the second dice

the probability to get 1 is

3/6 = 1/2

the probability to get 6 is

2/6= 1/3

the chance to get 1 and 3 is

1/2 * 1/3 = 1/6

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