A dice is rolled 100 times, then the minimum number of times'1' is occurred on the top face is
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n(S)=100
Let A be the event in which we get 1
:.n(A)=100
:. P(A)=n(A)÷n(S)
=100÷100
=1
:.P(A)=1
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Probability of getting 1 on the top face =
Number of Favorable Outcomes / Total Number of Possible Outcomes
Probability of getting 1 on the top face = 100/100
= 1
The number 1 on the dice can appear on the top face all the times wen the dice is rolled.Thus Number of Favorable Outcomes is taken as 100.
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