Math, asked by ramkd003, 2 months ago

A dice is rolled 250 times and its outcomes are recorded as below:
Outcome
1
2
3
4
5
6
Frequency
35
45
50
38
53
29
Find the probability of getting
(i) an odd number. (ii) getting a prime number.​

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Answers

Answered by arthsoni30
11

Answer:

(1) 0.552

(2) 0.592

Step-by-step explanation:

(1) The probability of getting an odd number would be equal to favourable outcome/total outcomes.

Here favourable outcomes would be number 1,3, and 5.

So total favourable outcomes=35+50+53=138

Probability = 138/250

Probability = 0.552

(2) The favourable outcomes of prime numbers would be numbers 2,3 and 5 ( 1 is neither prime nor composite)

So total favourable = 45+50+53 = 148

Probability = 148/250

= 0.592

Hope it helps you :D

Answered by ThatThinker
4

Here you go:

  • The Probability of getting an odd number will be:

Total number of outcomes = 250

Total number of outcomes = 250Total number of outcomes of getting odd numbers = 35 + 50 + 53 = 138

Total number of outcomes = 250Total number of outcomes of getting odd numbers = 35 + 50 + 53 = 138P (getting an odd number) = 138 / 250 = 69 / 125

The Probability of getting a prime number will be:

Total number of outcomes = 250

Total number of outcomes of getting prime numbers = 53+50+45 = 148

which will be 148/250 = 74/125

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