Question

A dice is rolled twice. Find the probability that (i) 5 will not come up either time. (ii) 5 will
come up exactly one time.​

Answer 1

ANSWER~♪

$Total \: event =6×6=36$

$Events \: of \: getting  \: 5 are =$

$\small \boxed {(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(1,5),(2,5),(3,5),(4,5),(6,5)}$

$probability (e)= \frac{favourable \: outcomes}{total \: outcomes}$

$probability \: of \: getting 5 = \frac{11}{36}$

$probability \: of \: not\: getting 5 =1 - \frac{11}{36} = \frac{25}{36}$

$\small{ probability \: of \: getting 5 exactly \: one \: time \: is =} \boxed{ \frac{10}{36} }$

Answer 2

Answer:

your answer is 10/36 please thanks mr