Question

A dice is rolled twice. What is the probability that a 5 will show the first time and 3 in second time? ​

Answer 1

the probability is 1/5

Answer 2

Answer:

Step-by-step explanation:

probability = favourable conditions / total conditions possible

probability of event E = P(E)

P(5 on dice) = 1/6

P(3 on dice) = 1/6

now, if probability of case 1 = a and probability of case 2 = b

then combined probability of both case 1 and 2 together = ab

therefore= P(first 5 and then 3 on dice) = 1/6 x 1/6

ANSWER = 1/36

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