Question

A dice is rolled twice what is the probability that the number in the second roll will be higher than the first

Answer 1

Step-by-step explanation:

S = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

n(S) = 36

A is the event of getting no. in the second higher than the first.

A = {(1,2) (1,3) (1,4) (1,5) (1,6) (2,3) (2,4)

(2,5) (2,6) (3,4) (3,5) (3,6) (4,5) 4,6)

(5,6)}

n(A) = 15

therefore....

P(A) = n(A) / n(S) = 15/36 = 0.416