Question

a dice is throwm once .find the probability of getting a number that is niether prime nor composite.

Answer 1

When a dice is thrown
S= [1,2,3,4,5,6]
n(S) = 6

Let A be the event getting a number neither prime nor Composite
A = [ 1 ] i.e. n(A) =1
P(A) = n(A)/n(S)
=1/6

Probability of getting a number that is niether prime nor Composite is 1/6.

I hope this helped you.

Answer 2

Answer:

1/6

Step-by-step explanation: