a dice is throwm once .find the probability of getting a number that is niether prime nor composite.
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When a dice is thrown
S= [1,2,3,4,5,6]
n(S) = 6
Let A be the event getting a number neither prime nor Composite
A = [ 1 ] i.e. n(A) =1
P(A) = n(A)/n(S)
=1/6
Probability of getting a number that is niether prime nor Composite is 1/6.
I hope this helped you.
S= [1,2,3,4,5,6]
n(S) = 6
Let A be the event getting a number neither prime nor Composite
A = [ 1 ] i.e. n(A) =1
P(A) = n(A)/n(S)
=1/6
Probability of getting a number that is niether prime nor Composite is 1/6.
I hope this helped you.
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Answered by
2
Answer:
1/6
Step-by-step explanation:
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