Question

A dice is thrown 100 times and the outcomes are noted as given below:
ol getting (1) 2
Outcome
1
2
3
4
5
6
Frequency
21
5
6
14
18
15
23
9
When a dice is thrown at random, what is the probability of getting a (1) 3, (11) 6, (111) 4, (iv) 1?​

Answer 1

) P(Getting a number 3) = \dfrac{7}{50}

50

7

ii) P(Getting a number 5) = \dfrac{9}{50}

50

9

iii) P(Getting a number 4) = \dfrac{23}{100}

100

23

iv) P(Getting an even number) = \dfrac{47}{100}

100

47

v) P(Getting an odd number) = \dfrac{53}{100}

100

53

Step-by-step explanation:

The given table:

Outcomes: 1 2 3 4 5 6

Frequency: 21 9 14 23 18 15

Total number of possible outcomes = 100

i) 3

Number of favourable outcomes = 14

∴ P(Getting a number 3) = \dfrac{14}{100}

100

14

= \dfrac{7}{50}

50

7

ii) 5

Number of favourable outcomes = 18

∴ P(Getting a number 5) = \dfrac{18}{100}

100

18

= \dfrac{9}{50}

50

9

iii) 4

Number of favourable outcomes = 23

∴ P(Getting a number 4) = \dfrac{23}{100}

100

23

iv) Even number

Number of favourable outcomes(2, 4, 6) = 9 + 23 + 15 = 47

∴ P(Getting an even number) = \dfrac{47}{100}

100

47

v) Odd number

Number of favourable outcomes(1, 3, 5) = 21 + 14 + 18 = 53

∴ P(Getting an odd number) = \dfrac{53}{100}

100

53