Question

A dice is thrown 200 times and the outcomes are as follows
Outcomes: 1,2,3,4,5,6
Frequency: 40,32,32,25,38,33
If a dice is thrown at random.find the probability of getting the following
(A)1
(B)3
(C)6
(D)an odd number
(E)even number

Answer 1

Answer:

if correct then let me know and follow me.

Answer 2

Given:-

• A dice thrown 200 times outcome as follow
• 1 = 40
• 2 = 32
• 3 = 32
• 4 = 25
• 5 = 38
• 6 = 33

To find:-

• probability of getting
• 1
• 3
• 6
• an odd number
• an even number

Solution:-

hence,

as per first condition

A = 1

total out come = (40)

$p(a) = \frac{n(a)}{n \: (s)} = \frac{40}{200} = \frac{1}{5}$

as per second condition

B = 3

total out come of probability getting 3 is 32

$p(b) = \frac{n(b)}{n(s)} = \frac{32}{200} = \frac{16}{100} = \frac{4}{25}$

as per 3 rd condition ,

C =6

total out come of probability getting 6 is 33

$p(c) = \frac{n(c)}{n(s)} = \frac{33}{200}$

as per 4th condition

D = an odd number

as per this condition odd number total number of out come of probability is 1 , 3 , 5

40 + 32 + 38 = 110

$p(d) = \frac{n(d)}{n(s)} = \frac{110}{200} = \frac{11}{20}$

as per 5 th conditiom

E = even number

as per this condition even number total number of out come of probability 2 , 4 and 6

32 + 25 +33 = 90

$p(e) = \frac{n(e)}{n(s)} = \frac{90}{200} = \frac{9}{20}$