A dice is thrown 420 times abd the numver 6 is obtained 63 times,express the frequency of obtaining the number 6 as a percentage
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6 no. occur 63 times=6×63=378
So % will be =378/420 ×100=90%
So % will be =378/420 ×100=90%
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Thank you so much for asking this question:
Here is your answer:
We know that total number of outcomes will be n(s) = 420
And also number 6 is obtained 63 times
probability p(E)= n(E)/n(s)
= 63/420
=3/20
The percentage would be
3/20×100%
= 15%
If there is any confusion please leave a comment below.
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