Question

A dice is thrown 65 times and 4 appeared 21 times. Now in a random throw of a dice what is the probability of getting a 4?

Answer 1

HERE IS UR ANSWER
IT IS GIVEN THAT WHEN DICE IS TROWN 65 TIMES AND 4 APPEARED 21 TIMES.
BUT NOW WHEN DICE IS THROWN RANDOMELY
THEN THE PROBABILITY OF 4 COMES IS-----
total no of outcomes are 6
probability of 4 comes = 1
p(E)= FAVOURABLE OUTCOMES/TOTAL NO. OF OUTCOMES
=1/6
SO THE PROBABILITY OF GETTING 4 FOR THIS THROW IS 1/6.
HOPE It HELPS UHH..✌️✌️✌️

Answer 2

Answer:

Probability of getting a 4 is $\frac{21}{65}$

Step-by-step explanation:

Total number of tria1s $=65 .$

Number of times 4 appeared $=21 .$

Probability of getting a $4=$ $\frac{Number of times 4 appeared}{Total number of trials}$

$=\frac{21}{65}$