Question

a dice is thrown 80 times. if the probability of having an even number is 7/10 then how many times and odd number appears on dice?​

Answer 1

Answer:

Step-by-step explanation:

probability of even number=7/10

sum of all probabilities =1

probability of having odd number= 1-7/10

                                                       =10-7/10

                                                        =3/10

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Answer 2

There are 24 times that an odd number appears on dice.

Step-by-step explanation:

Since we have given that

Probability of having an even number = $\dfrac{7}{10}$

Probability of having an odd number = $1-\dfrac{7}{10}=\dfrac{10-7}{10}=\dfrac{3}{10}$

Number of times a dice is thrown = 80 times

So, the number of times an odd number appears on dice is given by

$\dfrac{3}{10}\times 80\\\\=3\times 8\\\\=24$

Hence, there are 24 times that an odd number appears on dice.

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A dice is thrown 80 times. If the probability of having an even number is 7/10 then how many times an odd number appears on dice?​

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