Question

A dice is thrown 9000 times and a throw of
three or four observed 3240 times so that the
dice cannot be regarded as an unbiased one
and find the limits between which the
probability of throw of 3 or 4 lies.

Answer 1

Answer:

SOLUTION: a dice is thrown 9000 times and 3 or 4 is observed 3240 times can we say dice is fair. Question 964030: a dice is thrown 9000 times and 3 or 4 is observed 3240 times can we say dice is fair. probably not, based on the following test. mean = n * p = 9000 * 1/3 = 3000.

Answer 2

n = 9000

p (3 or 4) = 1/6 + 1/6 = 2/6 = 1/3

(1-p) = 2/3

mean = n * p = 9000 * 1/3 = 3000

standard error = sqrt (n * p * (1-p) = sqrt ( 9000 * 1/3 * 2/3) = sqrt(2000) = somewhere between 44.72 and 44.73, the exact value not being important for this problem.

a raw score of 3240 will generate a z-score of (x-m) / se which would be equal to:

z = (3240 - 3000) / 44.72 or 44.73.

Therefore, z = 5.367 or 5.366.

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