Question

a dice is thrown. find the probability of getting " at most 2",and" at least 2"

Answer 1

Here is your answer
S={1,2,3,4,5,6}
n(S)=6
let A be the event of getting at the most 2
A={1,2}
n(A)=2
p(A)=n(A)/n(S)
p(A)=2/6
p(A)=1/3

Let B be the event of getting atleast 2
B={2,3,4,5,6}
n(B)=5
p(B)=n(B)/n(S)
p(B)=5/6
hope it's helpful