Question

A dice is thrown once. Find the probability of getting a prime number ​

Answer 1

Answer:3/6=1/2

Step-by-step explanation:

Total no. of outcomes = 6

no. of outcomes = prime nos. are 2,3,5

=> 3therefore P(getting a prime no. ) = 3/6= 1/2

Hope this is helpful

Answer 2

There are 6 numbers in a dice, 1,2,3,4,5,6 in which the prime numbers are 1, 3 and 5

Number of favourable outcomes= 3 (as there r 3 prime nos)

Total number of outcomes= 6

P(getting a prime number) is given by

$\frac{no \: of \: favourable \: outcomes}{total \: no \: of \: outcomes} = \frac{3}{6} = \frac{1}{2} = 0.5$

I think u got it

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