Question

a dice is thrown once. find the probability of getting a prime number​

Answer 1

SOLUTION

Possible numbers of events on throwing a dice = 6

Numbers on dice = 1,2,3,4,5 and 6 

(i) Prime numbers = 2, 3 and 5

Favourable number of events = 3

Probability that it will be a prime number = 3/6 = 1/2

Answer 2

Answer:

A dice is thrown once , possible outcomes are 1,2,3,4,5,6,

:) number of all possible outcomes = 6

prime number are 2,3,5

number of prime number =3

$p(e) = \frac{number \: of \: fvourable \: outcomes}{total \: number \: of \: outcomes} \\ \\ p(e) = getting \: a \: prime \: numer = \frac{3}{6} = \frac{1}{2}$