a dice is thrown once . find the probability of getting a multiple of 2 and 3
ram242:
probablity=1/2
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total multiples- 2,3,4,6=4
total outcomes=6
probability=4/6
=2/3
total outcomes=6
probability=4/6
=2/3
4 to 6
hey it is wrong
2c1/6c2 i s the answer
sorry i am wrong
Answered by
4
a DIE (proper singular) can show 1,2,3,4,5 or 6.
The Event that a multiple of 2 or 3 is satisfied when 2, 3, 4 or 6 is rolled, so P(Event) = 4/6 = 2/3.
The Event that a multiple of 2 or 3 is satisfied when 2, 3, 4 or 6 is rolled, so P(Event) = 4/6 = 2/3.
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