A dice is thrown once find the probability of getting a number which (i) is a prome no. (ii) lies between 2 and 6
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3
total outcomes in dice =1,2,3,4,5,6
For prime ni:
Favourable outcome=1,3,5
Probability=total outcome/possible favourable outcomes.
P(e)=3/6
=1/2
For 2nd case
Sample space for no. lie between 2&6 are;
{3,4,5}
P(e)=3/6
=1/2.
Mark brainliest
For prime ni:
Favourable outcome=1,3,5
Probability=total outcome/possible favourable outcomes.
P(e)=3/6
=1/2
For 2nd case
Sample space for no. lie between 2&6 are;
{3,4,5}
P(e)=3/6
=1/2.
Mark brainliest
Answered by
1
Answer: here,total no.of outcomes are 6
Now,
F=3
P(of getting prime no.) = F/N
=3/6
=1/2
F =3
P(of getting no.between 2and 6) =F/N
=3/6
=1/2
Step-by-step explanation:
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