A dice is thrown once. Find the probability of getting a odd nobmer
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No of outcomes - 6
No of favourable outcomes - 3
Let E be the event of getting a odd number
Then
P(E) = 3/6 = 1/2 Ans....
No of favourable outcomes - 3
Let E be the event of getting a odd number
Then
P(E) = 3/6 = 1/2 Ans....
Answered by
4
total outcome=6
p(odd number in dice)= n(e)/n(s)
odd number =1 3 5
so 3/6=1/2
p(odd number in dice)= n(e)/n(s)
odd number =1 3 5
so 3/6=1/2
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