A dice is thrown once. Find the probability of getting
(i) a prime number greater than 2. (ii) an even number.
(iii) a number lying between 3 and 8. (iv) an even number or a multiple of 3.
Answers
Answer:
(i) P(E) = 2/6 = 1/3
(ii) P(E) = 3/6 = 1/2
(iii) P(E) = 3/6 = 1/2
(iv) This is the answer for multiple of 3 : P(E) = 2/3
This is the answer for even no. : P(E) = 3/6 = 1/2
This is the answer for both even no. and multiples of 3 : P(E) = 1/6
Answer:
1)1/3
2)1/2
3)1/2
4)3/4
Explanation:
We know dice have 6 sides ,ie, 1, 2, 3, 4, 5, 6
1)Prime numbers grater than 2 on a dice are 3, and 5.
So, the total number of prime numbers is 2.
we know :-
Thus, probability of getting a prime number = 1/3
2)Even numbers on a dice are 2, 4 and 6.
So, the total number of even numbers is 3.
we know :-
Thus, probability of getting a even number = 1/2
3)Number lying between 3 and 6 are 4, 5
So,total number lying between 3 and 6 is 2
we know :-
Thus, probability of number lying between 3 and 8 = 1/3
4)Number of even number or a multiple of 3 are 2, 3, 4, 6
So,total number of even number or multiples of 3 is 4
we know :-
Thus, probability of number lying between 3 and 8 = 2/3
☆Know more☆
Prime number :- A number that have only 2 factors: 1 and themselves.
For example,
11 is a prime because it is divisible only by 1 and it’s number itself.
Even number :- A number which is divisible by 2.
For example,
22 is a even number because it exactly divisible by 2.
Odd number :- A number which can’t be divisible by 2.
For example,
33 is a odd number because it i not exactly divisible by 2.