Question

A dice is thrown once. Find the probability of getting:

(i) a prime number.

(ii) a number lying between 2 and 6.

(iii) an odd number.

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Answer 1

Answer:

Probability of getting:

(i) a prime number     =     2,3,5

    = 3/6 = 1/2

(ii) a number lying between 2 and 6   =   3,4,5

    = 3/6 = 1/2

(iii) an odd number    =    1,3,5

    = 3/6 = 1/2

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Answer 2

Answer:

P ( prime no.) = 3/6 = 1/2

P ( no. b/w 2 and6) = 5/6

P ( odd no.) = 2/6 = 1/3 (Ans.)

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