a dice is thrown once .find the probablity of getting (1)odd number (2)prime number(3)a number greater than 2 pn the dice
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hey mate here is your answer.........
●1 odd no.= 3
Probability = favourable outcome / total outcome
1 / 6.
●2 prime no.
6/ 6 = 1
●3 no. greater than 2.
4/6= 2/3
i hope this helps you..........
mark me brainliest
●1 odd no.= 3
Probability = favourable outcome / total outcome
1 / 6.
●2 prime no.
6/ 6 = 1
●3 no. greater than 2.
4/6= 2/3
i hope this helps you..........
mark me brainliest
vibhamalviya8:
pls mark me brainliest
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