A dice is thrown once the proability of getting the square of the number appearing an the dice to be a multiple of 9
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Find the total possible outcome:
A dice has 6 sides
Therefore the total possible outcome = 6
Find the squares of the numbers on each side:
1² = 1
2² = 4
3² = 9 {Which is a multiple of 9)
4² = 16
5² = 25
6² = 66 (Which is a multiple of 9)
Find the total favourable outcome:
Total number of favourable outcome = 2
(Which is 3 and 6)
Find the probability of getting the square of the number appearing an the dice to be a multiple of 9:
P(square is a multiple of 9) = 2/6 = 1/3
Answer: The probability is 1/3
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