A dice is thrown once. The probability of getting an odd number is
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3/6=1/2 is the answer...
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suppose 'S' is the sample space.
S = { 1 , 2 , 3 , 4 , 5 , 6 }
n ( s ) = 6
Event A : getting an odd number.
A = { 1 , 3 , 5 }
n ( A ) = 3
P ( A ) = n ( A ) / n ( s )
= 3 / 6
= 1 / 2
therefore the probability of getting an odd number is 1 / 2.
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