a dice is thrown once. the probability of getting the square of the no. appearing on the dice to be a multiple of 9 is
Answers
Answered by
5
Square of 1 = 1
Square of 2 = 4
Square of 3 = 9
Square of 4 = 16
Square of 5 = 25
Square of 6 = 36
Hence, no. of favourable outcomes = 2
Total no. of outcomes = 6
Hence, probability = 2 ÷ 6 = 1 ÷ 3
Square of 2 = 4
Square of 3 = 9
Square of 4 = 16
Square of 5 = 25
Square of 6 = 36
Hence, no. of favourable outcomes = 2
Total no. of outcomes = 6
Hence, probability = 2 ÷ 6 = 1 ÷ 3
tia4204:
please tell the means of favourable outcomes here
by the way thanks for giving response
Favourable outcomes means the outcome which is in the favour of condition given. In your ques, it means the no. of outcomes in which square of the no. appearing on dice is a multiple of 9.
ok I got it
thank you very much
Mention not
Similar questions