A dice is thrown once. The probability of getting the square of the number appearing on the dice to be a multiple of 9 is???
Answers
We know, when a dice is thrown once the outcomes are 1, 2, 3, 4, 5, 6.
The square of the outcomes are 1, 4, 9, 16, 25 and 36.
Now, the square of the number appearing on the Dice to be a multiple of 9 are 9 and 36.
Hence, the probability of getting the square of the number appearing on the Dice to be a multiple of 9 = 2/6=1/3
Therefore,
the probability of getting the square of the number appearing on the Dice to be a multiple of 9 =1 We know, when a dice is thrown once the outcomes are 1, 2, 3, 4, 5, 6.
The square of the outcomes are 1, 4, 9, 16, 25 and 36.
Now, the square of the number appearing on the Dice to be a multiple of 9 are 9 and 36.
Hence, the probability of getting the square of the number appearing on the Dice to be a multiple of 9 = 2/6=1/3
Therefore,
the probability of getting the square of the number appearing on the Dice to be a multiple of 9 =1/3