a dice is thrown once what is the probability of getting old primes ?
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Answered by
0
no. of odd prime is 2
i.e 3 5
total no. of events =6
so the probability of getting odd prime no. = 2/6 => 1/3.
i.e 3 5
total no. of events =6
so the probability of getting odd prime no. = 2/6 => 1/3.
Answered by
1
odd prime no = 2
they are 3 ,5
total no. of events =6
p(E) = favorable outcome/ total outcome
= 2/6
= 1/3.
they are 3 ,5
total no. of events =6
p(E) = favorable outcome/ total outcome
= 2/6
= 1/3.
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