Question

a dice is thrown once what is the probability of throwing at 4​

Answer 1

Step-by-step explanation:

(i) Let E1 = event of getting the number 4. Then, E1={4} and, therefore, n(E1)=1.

∴ P(getting the number 4) =P(E1)=n(E1)n(S)=16.

Answer 2

Answer:

No.of numbers in a dice = 6

We already know that probability = No.of favorable conditions / total no.of favorable conditions

So,

Probability of getting 4 = 1/6

Hope it helps you!