A dice is thrown rwice. What is the probability that the same number will come up either time?
Answers
Answered by
0
Answer:
1/6
Step-by-step explanation:
Answered by
0
Answer:
p(A) = 6
Step-by-step explanation:
A Dice is thrown twice
S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
n(S) = 36
'Let A be the probability that the same number will come up either time'
A = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}
n(A) = 6
p(A) = n(A) / n(S)
p(A) = 6 / 36
p(A) = 6
Similar questions