Math, asked by mnavneeth4528, 1 year ago

A dice is thrown rwice. What is the probability that the same number will come up either time?

Answers

Answered by AkshitSinghvi
0

Answer:

1/6

Step-by-step explanation:


Answered by polprathamesh7
0

Answer:

p(A) = 6

Step-by-step explanation:

A Dice is thrown twice

S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

     (2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

     (3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

     (4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

     (5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

     (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

n(S) = 36

'Let A be the probability that the same number will come up either time'

A = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

n(A) = 6

p(A) = n(A) / n(S)

p(A) = 6 / 36

p(A) = 6


       

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