Question

a dice is thrown thrown twice what is the probability that 5 will not come up any time ​

Answer 1

Answer:

Throwing a die twice and throwing two dice simultaneously are treated as the same experiment.

Sample space ={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

i) P(5 will not come up either time)= Number of times 5 does not show divided by total number of outcomes(5 will not come up either time)=

36

25

ii) P(5 will come up at least once)= Number of times 5 shows up at least once divided by total number of outcomes

P(5 will come up at least once)=

36

11

Answer 2

Answer:

$\frac{5}{6}$

Step-by-step explanation:

U={1,2,3,4,5,6}

P(Not Getting 5 any time)=

$\frac{5}{6}$