Question

A dice is thrown twice and outcomes is recorded in form of ordered pair of number. If we get the number i in first toss and the number j on second toss that is recorded as (ij) where i = 1,2,3,4,5,6 and j =1,2,3,4,5,6 find probability that sum of i and j is 8​

Answer 1

Answer:

5/36

Step-by-step explanation:

n(S) = 36

A = { (2,6),(3,5),(4,4),(5,3),(6,2)}

n(A) = 5

P(A) = n(A) / n(S) = 5/36