Question

A dice is thrown twice find probability of sum of5

Answer 1

Answer:

the dice may be thrown as 1st : 2 & 2nd:3

Step-by-step explanation:

     so, 2+3 = 5

                         →  hence solved

Answer 2

Step-by-step explanation:

n(S) = 36.

Let A be the event of getting sum as 5.

A = {(1,5),(2,3),(3,2),(4,1)}

n(A) = 4.

p(A) = n(A)/n(s)

= 4/36.

= 1/9.

hope this helpß u(^^)