A dice is thrown twice. Find the probability of getting a doublet.
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Answer:
Answer:
1/6
Step-by-step explanation:
Given : A die is thrown twice.
To find : The probability of the events (getting a doublet)
Solution :
When two dice rolled once the outcome will be,
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Now,
The probability of the events (getting a doublet)
Favorable outcome are : (1,1) ,(2,2), (3,3), (4,4), (5,5), (6,6)
So, Favorable outcome = 6
Total number of outcome = 36
=> 6/36=1/6
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