Question

A dice is thrown twice find the probability of getting prime number as asum ?

Answer 1

Numbers in a cube =1,2,3,4,5,6
Numbers in a cube which are prime number=2,3,5
Therefore, No. of prime numbers in two cubes=6
No. of numbers in two cubes=12
Therefore, probably of getting a prime number in two cubes= 6/12=1/2

Answer 2

The probability of getting prime number as a sum is   $\frac{5}{12}$

Step 1: Given data

A dice is thrown twice.

Step 2:To find:

To find the probability of getting prime number as a sum.

The total number of possible outcomes( sample space) for two times dice are 36.  They are

{  (1,1), (1,2),  (1,3), (1,4), (1,5), (1,6)

 (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), ((3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)                                      

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6) }  

  n(S) = 36  

Hence, the favorable outcomes to getting the prime numbers a sum is (1,1), (1,2), (1,4), (1,6), 2,1), (2,3), (2,5), (3,2), (3,4), (4,1), (4,3), (5,2), (5,6), (6,1), (6,5),

Hence their is to get the prime number as a sum is 15.

 n(A) =15               

Formula used:

 P(A) =  $\frac{n(A)}{n(S)}$

where,

P(A) refers the probability,

n(A) refers the number of favorable possibility,

n(S) refers the number of Total sample space.

Hence.

$P(A)=\frac{15}{36}$

$P(A)=\frac{5}{12}$

Hence the probability of getting prime number as a sum is   $\frac{5}{12}$

To learn more..

1) In a throw of two dice,find the probability of getting a sum of 10

https://brainly.in/question/2123438

2) n a simultaneous throw of two dice find the probability of getting a total of 8

https://brainly.in/question/2822858