Question

A dice is thrown twice. The probability of
getting 4, 5 or 6 in the first throw and 1,2,3
or 4 in the second throw is:
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Answer 1

Option (2) ⅓

The probability of getting 4, 5, or 6 in first throw = 3/6 = ½

The probability getting 1, 2, 3, or 4 in second throw = 4/6 = ⅔

Hence, the required probability = (½).(⅔)

= 2/6

=⅓.

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Answer 2

answer of your question