Question

a dice is thrown twice. the probability of getting 4,5or6 in the first and 1,2,3or4 in thee second throw is

Answer 1

Answer:

probability of getting 4, 5 or 6 in the first throw=3/6

                                                                                    =1/2

probability of getting  1,2,3 or 4 in the second throw =4/6

                                                                                      = 2/3

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Answer 2

Answer:

1/3

Step-by-step explanation:

The probability of getting 4, 5, or 6 in first throw = 3/6 = ½

The probability getting 1, 2, 3, or 4 in second throw = 4/6 = ⅔

Hence, the required probability = (½).(⅔)

= 2/6

=⅓.