A dice is thrown twice. What is the probability that
a) 5 will not come up either time?
b) 5 will come up at least once?
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RohitS45:
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n(s)=36
n(E1)=25
p(E1)=n(E1)/n(s)
=25/36
n(e2)=11
p(e2)=n(e2)/ns
=11/36
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