A dice is thrown twice . What is the probability that at least one of them comes up with number 4
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Step-by-step explanation:
Probablity is 11/36
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P (E) = No. of favourable outcomes /
total no. of outcomes
No. of favourable outcomes = (1,4) (2,4) (3,4)(4,4) (5,4) (6,4) (4,1) (4,2) (4,3) (4,5) (4,6)
total outcomes =36
p (at least one of them is 4) =11/36
don't forget to mark as brainliest. ...
total no. of outcomes
No. of favourable outcomes = (1,4) (2,4) (3,4)(4,4) (5,4) (6,4) (4,1) (4,2) (4,3) (4,5) (4,6)
total outcomes =36
p (at least one of them is 4) =11/36
don't forget to mark as brainliest. ...
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