Math, asked by g9505717608, 1 day ago

a dice is thrown twice. what is the probability that (I)3 will not come up either time?,(Ii) 3 will come up at least once?​

Answers

Answered by krishnapriyap0987
2

ANSWER

Correct answer is C

STEP BY BY ELXPANATION

When a dice is thrown twice, the possible 36 outcomes.

3 will not come up either time, when pair of outcomes are anything except (1,3),(3,1),(3,3),(2,3),(3,2),(3,6),(6,3)(4,3),(3,4),(3,5),(5,3)

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Probability that 3 will not come up either time =

36

36−11

=

36

25

6 will come up at least once, when pair of outcomes are (1,6),(6,1),(6,2),(2,6),(3,6),(6,3),(4,6),(6,4),(6,5),(5,6),(6,6)

Probability that 6 will come up at least once =

36

11

Answered by bkarki594
2

Step-by-step explanation:

OUT of 36 possible outcome in 11 outcome there will be 3. this means the probability of getting 3 in either roll is 11/36.

probability not 3 is (36-11)/36.

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