Question

A dice is thrown twice.What is the probability that sum of two numbers on the top of the dice is 8

Answer 1

HEY MATE HERE IS YOUR ANSWER

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The sum of numbers on the top of dice = 8

Total numbers pf dice = 1 +2+3+4+5+6 = 21

$= > \: probability \: = \frac{sum \: of \: no. \: on \: top}{total \: no. \: of \: sum \: }$
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$= > \frac{7}{36} \: answer$

Answer 2

hi there!
Here's the answer:

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Let S be sample space
n(s) - No. of total outcomes when 2 dice are rolled.

n(S) = 6² = 36
{ °•° No. of total outcomes when n dice are rolled = 6^n }


Let E be the Event that sum of the numbers on the two dice after rolling is 8.
n(E) - No. of favourable outcomes for Event E .

Possible cases (or)
E = {(1,7,) , (2,6) , (3, 5) , (4,4) , (5,3) , (6,2) , (7,1) }

n(E) is nothing but No. of possible cases in Set E
•°• n(E) = 7.

Probability of an Event
=No. of Favourable outcomes of that Event ÷ No. of Total Outcomes

= n(E) / n(S)

•°• P(E) = 7/36.



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Hope it helps