Math, asked by priya1234568763, 19 days ago

A dice is thrown. What is the probability of getting a number divisible by 5​

Answers

Answered by Ooguay
1

Answer:

\frac{1}{6}

Step-by-step explanation:

Total No.of outcomes = 1,2,3,4,5,6 = 6

Number divisible by 5 = 5x1 =5 = 1

Probability of an event = \frac{No. of favourable .outcomes}{Total. No.of outcomes}

= \frac{1}{6}

Answered by sheeb12ansari
0

Given: A dice is thrown.

We have to find the probability of getting a number divisible by 5.

For this, we are using the formula of probability: P(A)=\frac{n(A)}{n(S)}

As we know that dice is thrown means the total number of outcomes will be6.

We are solving in the following way:

Sample space (S) = 1,2,3,4,5,6

\thereforeThe total number of outcomes n(S) = 6

And the probability of getting a number divisible by 5will be:

From the above sample space, we can see that only the number5 is divisible by5.

\therefore The number of favourable outcomes n(A)=1

\therefore P(A)=\frac{n(A)}{n(S)} \\\\=>P(A)=\frac{1}{6}

Hence, the probability of getting a number divisible by 5will be\frac{1}{6}.

Similar questions