Question

A dice is tossed 15 times. The number 2 appears 5 times and the number 6 appears 7 times etc. what is the
probability of getting the number 6?

Answer 1

Answer:

This probability is 1 minus the probability that all outcomes are different, just like in the birthday problem.

The first throw can be anything (probability 1), the second must be unequal the first so probability 56, the third unequal to the previous 2, so 46, and so on till the fifth, which has two options left, so 26. Multiply these, and take one minus that.

This comes to (if I computed correctly) to 4954=0.9074074074…, so I think your answer was correct in the first place (maybe an exact answer was asked for instead of a decimal approximation?) It's also the same as the answer by ADG.

Answer 2

Answer:

7/90 is currect answer of