a dice is tossed once find the probability of getting a) a number 4 b) a number greater than 4 c)a number less than 4 d)an even number e)a number greater than 6 f)a number less than 7
Answers
Answered by
25
Step-by-step explanation:
(i) Here, let E be the event ‘getting a number greater than 4’.
The number of possible outcomes is six : 1, 2, 3, 4, 5 and 6, and the outcomes favourable to E are 5 and 6. Therefore, the number of outcomes favourable to E is 2. So,
P(E) = P(number greater than 4) =2/6 =1/3
(ii) Let F be the event ‘getting a number less than or equal to 4’.
Number of possible outcomes = 6
Outcomes favourable to the event F are 1, 2, 3, 4.
So, the number of outcomes favourable to F is 4.
Therefore, P(F) =4/6 =2/3
Are the events E and F in the example above elementary events?
No, they are not because the event E has 2 outcomes and the event F has 4 outcomes.
Similar questions