Math, asked by bhargavi3813nms, 7 months ago

A dice is tossed once. Find the probability of getting
i. a number 5
ii. a number greater than 5
iii. a number less than 5
iv. an odd number
v. an even number
vi. a number greater than 6​

Answers

Answered by saumya5873
17

Step-by-step explanation:

Total outcomes = 6

i)Favourable outcomes = 1 (5)

Probability = 1/6

ii)Favourable outcomes = 1 (6)

Probability = 1/6

iii) Favourable outcomes = 4 (1,2,3,4)

Probability = 4/6

= 2/3

iv) Favourable outcomes = 3 (1,3,5)

Probability = 3/6

= 1/2

v) Favourable outcomes = 3 (2,4,6)

Probability = 3/6

= 1/2

vi) Favourable outcomes = 0 (because the larger no. on dice is 6)

Probability = 0

Answered by kashyaprbala09
0

Answer:

i) 1/6
ii) 1/6
iii) 2/3
vi) 1/2
v) 0 because there is no larger number than 6 in a dice

Step-by-step explanation:

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