Question

A dice is tossed once. Find the probability of getting
(i) a number 5
(ii) a number greater than 5
(iii) a number less than 5
(iv) an odd number
(v) an even number


(Plese give me the answer

Answer 1

Answer:

1. 1/6
2. 1/6
3. 1/6
4. 1/3
5. 1/3

Step-by-step explanation:

hope it's help you

Answer 2

Answer:

1/6, 1/6, 2/3, 1/2, 1/2

Step-by-step explanation:

Given that A dice is tossed once.

So, all possible outcomes are:

{1,2,3,4,5,6}

(i)

In the outcome there is only one 5.

So, the probability of getting a number 5 = 1/6

(ii)

In the outcome the number greater than 5 is = {6}.

So, the probability of getting a number greater than 5 = 1/6

(iii)

In the outcome the numbers less than 5 is = {1,2,34}.

So, the probability of getting  a number less than 5 = 4/6 = 2/3

(iv)

In the outcome the odd numbers are = {1,3,5}.

So, the probability of getting an odd number = 3/6 = 1/2

(v)

In the outcome the even numbers are = {2,4,6}.

So, the probability of getting an even number = 3/6 = 1/2