a dice is tossed twice the probability of having a number greater than 4
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Numbers greater than 4=5&6
probability of having a no. greater than 4 when dice is toss twice =
Numbers greater than 4 ÷ Total outcoming numbers= 4÷12 =1÷3=1:3
probability of having a no. greater than 4 when dice is toss twice =
Numbers greater than 4 ÷ Total outcoming numbers= 4÷12 =1÷3=1:3
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There are 6 faces in dice. So, according to question we have excluded the numbers 1 to 4. The numbers left are 5 and 6. The formula for finding probability is Number of outcomes/Total number of experiments. By this formula putting the value
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