a dice numbers 1 to 6 units faces is rolled once find the probability of getting either an even number or multiple of 3 on its top face
Answers
Answered by
5
hey !!
Here's your answer !!
total outcomes=6
favourable outcomes=2,3,4,6(either even or multiple of 3)
hence,
required probability=favourable outcomes/total outcomes
=4/6
=2/3 (answer)
hope it helps !!
mark as brainliest !!
thank you :)
❤️✌️☺️
Here's your answer !!
total outcomes=6
favourable outcomes=2,3,4,6(either even or multiple of 3)
hence,
required probability=favourable outcomes/total outcomes
=4/6
=2/3 (answer)
hope it helps !!
mark as brainliest !!
thank you :)
❤️✌️☺️
Anonymous:
going to 10 this year ......
Answered by
0
Answer:
Step-by-step explanation:
POSSIBLE OUTCOMES =6
FAVOURABLE OUTCOMES FOR EITHER EVEN OR MULTIPLE OF
=2,4,6,3
PROBABILITY = FAVOURABLE OUTCOMES /TOTAL POSSIBLE OUTCOMES
=4/6
=2/3 ANS
HOPE IT HELPS..............
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