Question

a dice rolled once. find the probability of getting number greater than 0 and a multiple of 3
plz guys I need ur help ​

Answer 1

Answer:

1/3

Step-by-step explanation:

s = {1,2,3,4,5,6}

n(s)=6

event of getting >0 & 3multiples, A = {3,6}

n(A)=2

therefore p(A) = n(A)/n(s) = 2/6 = 1/3

Answer 2

Answer:

1/6

Step-by-step explanation:

There are 6 possibilities. Only 6is a number greater than 0 and multiple of 3.