Question

A dice thrown once. find the probability of getting
a) even number
c) number greater than 4
b) prime number
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Answer 1

$\large{\underline{\underline{\bold{\red{\sf{Question}}}}}}$

A dice thrown once. find the probability of getting

a) even number

c) number greater than 4

b) prime number

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$\large{\underline{\underline{\bold{\blue{\sf{Solution:.}}}}}}$

When a dice is thrown possibke outcomes are ⇒1,2,3,4,5,6..

$\large{\underline{\underline{\bold{\orange{\sf{Even\: No.}}}}}}$

The numbers that are dibisible by 2 are known as Even nunbers..For Eg:. 4,6,18,34 etc..

$\large{\underline{\underline{\bold{\red{\sf{Prime\: No.}}}}}}$

The numbers that are divisible by 1 and the number itself are known as Prime Numbers .For Eg:. 3,5,7 etc..

a) Even numbers⇒2,4,6

Total⇒3

Probability⇒$\frac{No.\:of\:fav\:Outcomes}{Total\:no.\:of\:Outcomes}$

⇒$\cancel\frac{3}{6}⇒\frac{1}{2}$

c)Number greater than 4 ⇒5 and 6

Total⇒2

Probability⇒$\frac{No.\:of\:fav\:Outcomes}{Total\:no.\:of\:Outcomes}$

⇒$\cancel\frac{2}{6}⇒\frac{1}{3}$

b)Prime numbers=3,2,5

Total⇒3

Probabilty⇒$\frac{No.\:of\:fav\:Outcomes}{Total\:no.\:of\:Outcomes}$

⇒$\cancel\frac{3}{6}⇒\frac{1}{2}$

Answer 2

Answer:

$\bigstar\boxed{(a)\frac{1}{2}}$

$\bigstar\boxed{(b)\frac{1}{3}}$

$\bigstar\boxed{(c)\frac{1}{2}}$

Step-by-step explanation:

Formula to be remembered :

• Probability = Number of possible outcomes/Total number of outcomes

Explanation:

Total numbers in a dice = 6 (1,2,3,4,5,6)

(a) even number = 2,4,6

→ No. of outcomes = 3

→ Probability = Number of possible outcomes/Total number of outcomes

→ Probability = 3/6 = 1/2

_____________________

(b) greater than 4 = 5,6

→ No. of outcomes = 2

→ Probability = Number of possible outcomes/Total number of outcomes

→ Probability = 2/6 = 1/3

_____________________

(c) prime number = 2,3,5

→ No. of outcomes = 3

→ Probability = Number of possible outcomes/Total number of outcomes

→ Probability = 3/6 = 1/2

______________________